Question

An eletric iron consumed energy at the rate of 840v when heat is in maximum ray and 360v and the heating as at minimum the voltage is 220v what are the current and resistance in each case

Answer 1

★QUESTION★:

An eletric iron consumed energy at the rate of 840v when heat is in maximum ray and 360v and the heating as at minimum the voltage is 220v what are the current and resistance in each case

★GIVEN★:

✦When heating at max rate

⟾Power,P=840W

⟾Potential difference,V=220v

✦When heating at minimum rate

⟾Power,P=360W

⟾Potential difference,V=220v

★CALCULATION:-★

•When heating maximum rate

We know P = VI

⇒ 840 = 220 × I

⇒ I = 840/220

⇒ I = 4 A

R = V/I = 220/4 = 55 Ω

⇥So current = 4A and resistance = 55Ω

•When heating is at minimum rate

We know P = VI

⇒ 360 = 220 × I

⇒ I = 360/220

⇒ I = 1.636 A

R = V/I = 220/1.636

= 134.45 Ω

⇥So current = 1.636 A and resistance = 134.45Ω

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