Question

An elevator and its load have a total mass of 800 kg. Find the tension T in the supporting cable when the elevator, originally moving downward at 10m/s is brought to the rest with constant acceleration at a distance of 25m.​

Answer 1

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An elevator and its load have a total mass of 800 kg. Find the tension T in the supporting cable when the elevator, originally moving downward at 10m/s is brought to the rest with constant acceleration at a distance of 25m.

Answer 2

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Given :-

Mass of Elevator along its load = m = 800 Kg

Initial Velocity = u = 10 ms-¹

Heights travelled = h = 25 m

Acceleration due to gravity = g = 10 ms-².

Using third equation of Motion to find acceleration of the body.

v² = u² - 2ah

u² = 2ah

a = u²/2h

a = 100/50

a = 2 ms-².

R u = m(g+a)

Let the tension R is acting in upward direction.

R u = 800(10+2)

R u = 9600 N

Answer 3

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

Given :-

Mass of Elevator along its load = m = 800 Kg

Initial Velocity = u = 10 ms-¹

Heights travelled = h = 25 m

Acceleration due to gravity = g = 10 ms-².

Using third equation of Motion to find acceleration of the body.

v² = u² - 2ah

u² = 2ah

a = u²/2h

a = 100/50

a = 2 ms-².

R u = m(g+a)

Let the tension R is acting in upward direction.

R u = 800(10+2)

R u = 9600 N

Answer 4

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

Given :-

Mass of Elevator along its load = m = 800 Kg

Initial Velocity = u = 10 ms-¹

Heights travelled = h = 25 m

Acceleration due to gravity = g = 10 ms-².

Using third equation of Motion to find acceleration of the body.

v² = u² - 2ah

u² = 2ah

a = u²/2h

a = 100/50

a = 2 ms-².

R u = m(g+a)

Let the tension R is acting in upward direction.

R u = 800(10+2)

R u = 9600 N

Answer 5

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

Given :-

Mass of Elevator along its load = m = 800 Kg

Initial Velocity = u = 10 ms-¹

Heights travelled = h = 25 m

Acceleration due to gravity = g = 10 ms-².

Using third equation of Motion to find acceleration of the body.

v² = u² - 2ah

u² = 2ah

a = u²/2h

a = 100/50

a = 2 ms-².

R u = m(g+a)

Let the tension R is acting in upward direction.

R u = 800(10+2)

R u = 9600 N

Answer 6

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

Given :-

Mass of Elevator along its load = m = 800 Kg

Initial Velocity = u = 10 ms-¹

Heights travelled = h = 25 m

Acceleration due to gravity = g = 10 ms-².

Using third equation of Motion to find acceleration of the body.

v² = u² - 2ah

u² = 2ah

a = u²/2h

a = 100/50

a = 2 ms-².

R u = m(g+a)

Let the tension R is acting in upward direction.

R u = 800(10+2)

R u = 9600 N