Question

an elevator car is moving upward with uniform acceleration of 2 metre per second square at the instance when its velocity is 2 metre per second upwards A ball is thrown to upward from its floor the ball Strikes Back the flow to second after its projection find the velocity of the projection of the ball relative to the lift​

Answer 1

Answer:

8 m/s

Explanation:

an elevator  acceleration = 2m/s²  ( upward)

Velocity = 2m/s

Distance covered in  1 sec = ut + (1/2)at²   = 2*1  + (1/2)2(1)² = 3 m

Let say Ball relative velocity = V

Time = 1 sec

acceleration = -g = -10 m/s²

Distance covered by ball & lift should be same to strike back

S = V(1) + (1/2)(-10)* 1²

=> 3 = V - 5

=> V = 8

the velocity of the projection of the ball relative to the lift​ = 8 m/s

Answer 2

Explanation:

wrongs answer given earlier.

right answer is 12m/s upward