Question

an elevator carry a weight of 1800kg is moving up with constant speed 2m/sec .the frictional force opposing the motion is 4000N. determine the maximum power delivered by the motor to the elevator.

Answer 1

We know that w = m * g

                            = 1800kg * 9.8

                            = 17640 N.

Given, frictional force opposing the motion.

So, F = weight + frictional force

         = 17640 + 4000 

         = 21640 N.

Minimum power delivered by the motor = F * V

                                                                    = 21640 * 2
 
                                                                     = 43280 W.



Hope this helps!