Math, asked by sona3458, 1 year ago

an elevator decends into a mine shaft at rate 5m/min .what will be the position in after l hour.​

Answers

Answered by vyomsharma53
2

300 metre

Step-by-step explanation:

Speed of the mineshaft's elevator = 5 metre per min.

1 hour = 60 min.

position of elevator after 1 hour = 60 x 5

= 300 metre

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