Math, asked by chaitanya1621, 1 year ago

An elevator decends into a mine shaft at the rate of 6 meters per minute .If the descent starts from 10 m above the ground level, how long will it take to reach -350 m​

Answers

Answered by Anonymous
7

Answer:

61 minutes

Step-by-step explanation:

Rate at which elevator decends into a mine shaft = 6m/min (Given)

Thus, in every minute, it goes down by 6m.

Rate of descent = 10m (Given)

Thus, we have 10m above the ground and 350 m below the ground

Therefore, the total distance = 20 + 350

= 370 m

Time taken = 370/6

= 61 minutes or 1 hour 1 minutes

Thus, the total time taken for elevator to reach 350m will be 61 minutes.

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