an elevator decends into an mine shaft at rate of 9m/min .how long if the decent starts from 10cm above the ground level will it take to reach (-350)m ?
(please answer it as fast as you could)
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Answer:
Time taken by elevator= initial position-final position
= 10-(-350)
= 360m
Time taken to reach 9m= 1min
Time taken to reach 360m= 360/9
= 40 min
∴ it will take 40 mins to reach 360m.
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