an elevator decends into an mine shaft at rate of 9m/min .how long if the decent starts from 10cm above the ground level will it take to reach (-350)m ?
(write full answer)
nairaditya312:
how
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2
Answer:
Step-by-step explanation:
initial position-final position
=10-(-350)
=360
Elevator desends at 9m/min
1/9min
1/9 into 360
=40 mins
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Answered by
0
Step-by-step explanation:
the answer will be 40 minutes. hope this answers will help you.
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