Question

An elevator decreases into a mine shaft at the rate of 5m per min.What will be its position after 1 hr?! suppose the distance above the ground represented by a positive integer and below the ground by a negative integer.​

Answer 1

Answer:

Given speed of the elevator = 5 m/min

time = 1 hour = 60 min

speed = distance/time

distance = speed×time = 5 × 60 = 300m

Since the distance is below the ground, the distance will be -300m.

The elevator will be 300m below the ground.

Step-by-step explanation:

Hope it helps. Mark as brainliest if it was helpful. Thank you.