An elevator desceds into a mine shaft at the rate of 6 m/min. if the descent starts from 10 m above the ground level , how long will it take to reach -350 m
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Total distance = 10-(-350)=360 m
T=d/S = 360/6 = 60 min or 1hr
T=d/S = 360/6 = 60 min or 1hr
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