Question

an elevator descend in a mine shaft at the rate of 6 metre per minute. if the decent starts from 20 metres above the ground level , how long wise the take to reach -340 metres?
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Answer 1

Answer:

1 hour that is 60 min

Step-by-step explanation:

so he started from 20 meter above and need to reach 340 down so total distance would be 340+20=360

for every minute its 6 meter , so for 360

its 360/6=60min that is one hour

mark me as brainliest ;)

Answer 2

Solution :

Rate of elevator             = -6 min

Total distance covered = 10 - ( -350 ) = 360m

time                                 = distance covered/Rate

$\frac{360}{60}$                                    = 60

time 60 min                    = 1 hr.

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$\frac{brainliest}{please}$

$@CutyMiley^{143}$