An elevator descend into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level , how long will it take to reach-350m.
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Step-by-step explanation:
Distance descended is denoted by a negative integer,
Initial height =+10 m
Final Depth =−350 m
Total distance to be descended by the elevator =(−350)−(+10)=−360 m
Given, the time is taken by the elevator to descend −6 m=1 minute
Thus, time taken by the elevator to descend −360 m= -360/-6
------- [from the formula : speed= distance/time ]
So it takes 60 min
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