Math, asked by jivendra, 1 year ago

An elevator descend into mine shaft at the rate of 5 meter per minute what will be position after one hour

Answers

Answered by gunjananand
5
5m/min
1 hour= 60min
After 1 hour=5*60=300m

So, it will reach 300m below the ground level.

gunjananand: pls mrk as braniliest
Answered by berinbhaskar205
7
Answer is 300m depth


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