Question

An elevator descend into mine shaft at the rate of 6m/min. If
the descend starts from 10 m above the ground level, how long
wall it take to reach-400 m?​

Answer 1

Answer:

68 minutes

Step-by-step explanation:

Given :- descent starting point = +10m

''. ending point = -400 m

therefore total distance to cover = 400+10

= 410 m

6m = 1 min time

so, 410 m = (410/6) m

= approx. 68 min

(ans) It will take 68 minutes for the elevator to reach -400m.

Answer 2

First we will calculate the distanve covered.

As, it started from 10m from ground level and reached 400 m, total distance covered

= | -400 m +10 m |

= l -390 m |

= 390 m

Now we have

Distance = 390 m

Speed = 6m/min

So time taken

$= \frac{distance}{speed}$

$= \frac{390}{6}$

$= 65 \: minute$