Math, asked by ssnk1000, 10 months ago

An elevator descends in a mine shaft at the rate of 5 metre per minute.
(i)What will be its position after one hour.
(ii)If it begins to descend down from 15 metre above the ground,what is its position after 45 minutes.
Whoever gives the answer first & step & step explaination in the answer he/she would be marked as the brainliest.

Answers

Answered by PriyanshuF9
2

Answer:

1: -300m

2: - 210m

Step-by-step explanation:

DISTANCE TRAVELLED IN 1 MINUTE = 5 METRES

DISTANCE TRAVELLED IN 1 HOUR I.E. 60 MINUTES = 5×60 = 300M BUT UNDER THE GROUND SO ANSWER IS -300M

DISTANCE TRAVELLED IN 45 MINUTES = 225

BUT IT STARTS 15 METRES ABOVE SO 225-15= 210

AND AS IT IS UNDER THE GROUND SO ANSWER IS -210M

PLEASE MARK AS BRAINLIEST

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