Question

an elevator descends in to a mine shaft at the rate of 5 m/min if the descend starts from 15m above the ground level how long will it Take to reach -360m​

Answer 1

Answer:

-210m

Step-by-step explanation:

(i) Displacement = Velocity x Time = -5 m/min x 60 min = -300 m.

(ii) Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m.

However, since we started 15 m above ground, displacement from the ground level = -225 + 15 m = -210 m.

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