Math, asked by suhanalthaf, 20 days ago

an elevator descends in to mine shaft at the rate 4/min .if the decent starts from 15 m above the ground level,
(1)what will be the position after 25 mins?
(2)how long will the elevator take to reach 165m below the ground level ,

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Answers

Answered by hollamahesha
0

Answer:

150 m/4 min  

so after 165 it will reach in 45 min

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