An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so
(i) what will be the position after 25min?
(ii) How long will the elevator take to reach 165m below the ground level
(Note its a 5 mark qquiestion)
I will note everyone as brainlinest and 105 point please answer
Answers
Answer:
Starting position of mine shaft is = 10m above ground
but,
it moves in opposite direction so it travels the distance (-350 m ) below the ground.
Total distance covered by mine shaft = 10m - (-350m)
= 10 + 350
= 360m
Now, taken to cover a distance of 6m by it = 1 minute
Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min6 1min
Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \61× 360 = 60 min
60 minutes = 1 hour
thus, in one hour the mine shraft reaches = 350 below the ground.
Answer:
An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so
An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so(i) what will be the position after 25min?
An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so(i) what will be the position after 25min?(ii) How long will the elevator take to reach 165m below the ground level
An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so(i) what will be the position after 25min?(ii) How long will the elevator take to reach 165m below the ground level(Note its a 5 mark qquiestion)
An elevator descends in to mine shaft at the rate of 4min. if the decent starts from 15m below ground,so(i) what will be the position after 25min?(ii) How long will the elevator take to reach 165m below the ground level(Note its a 5 mark qquiestion)I will note everyone as brainlinest and 105 point please answer
Step-by-step explanation:
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