Math, asked by thanksyoufor1k, 13 days ago

An elevator descends in to mine shaft at the rate of 6m/min. If the descent start from 10 m

above the ground level ,how long will it take to reach -350 m​

Answers

Answered by rimshakhan922009
2

Answer:

1 hour

Step-by-step explanation:

In 1 minute the elevator can descend = 6 metres

Total distance to be covered = -350+ 10 metre

= -360 metres

Time taken to cover -360 metres = -360÷6

= 60 minutes

= 1 hour

Hope it helps

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