An elevator descends in to mine shaft at the rate of 6m/min. If the descent start from 10 m
above the ground level ,how long will it take to reach -350 m
Answers
Answered by
2
Answer:
1 hour
Step-by-step explanation:
In 1 minute the elevator can descend = 6 metres
Total distance to be covered = -350+ 10 metre
= -360 metres
Time taken to cover -360 metres = -360÷6
= 60 minutes
= 1 hour
Hope it helps
Similar questions