Question

an elevator descends inta a mine shaft at a rate of 6m/min if the descent start from 10m above the ground level how long he will take to reach -350

Answer 1

Answer:

considering its 350 meters

total distance for the elevator to travel is = 10+350=360m

as 6m takes 1 min

360m will take 360/6 = 60 mins or 1 hr

Answer 2

Answer:

1 hour

Step-by-step explanation:

TOTAL TIME TAKEN=TOTAL DISTANCE COVERED/RATE OF DISCENT

=10+350/6=60 MINUTES IN AN HOUR