Math, asked by 0258, 1 year ago

An elevator descends into a mine at the rate of 6 meters per minute. If it begins to its descend from 15 meters above the ground, What will be its position after 45 minutes.

Answers

Answered by aashi14
4
speed is 6m/min
time is 45min
distance =speed×time
6×45=270m
this is from the starting position ie 15m above ground so the position is 255m below ground
Answered by TheRuhanikaDhawan
2
1min   -----     6 meters
45 min  -----     ?

45 x 6/ 1

=270 meters

case 1
given that elevator is 15 meters above the ground
so the elevator will be in the ground after 45 minutes

 case2
if there is place for it to go below the ground
it will go 270-15 = 255

255 meters below the ground

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