Question

an elevator descends into a mine shaft at a rate of 5 m/minute. if the descend start from 20 m above the ground level. how long will it take to reach 260 m.​

Answer 1

Answer:

Considering the elevator to be at constant speed and the destination to be 260 m below ground level,

The elevator has to travel 20m till the ground, then 260 m more.

So, the total distance to travel is 280 m

If the elevator's speed is 5 metres/minute,

Then

Time= Distance/Speed

       = 280/5

       =56 minutes

       

Thus the elevator would take almost 1 hour to reach its destination.

Step-by-step explanation:

Answer 2

Answer:

56 min

Step-by-step explanation:

260+20 = 280 m

Time taken = 280 ÷ 5

= 56 m