an elevator descends into a mine shaft at a rate of 5 m/minute. if the descend start from 20 m above the ground level. how long will it take to reach 260 m.
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Answer:
Considering the elevator to be at constant speed and the destination to be 260 m below ground level,
The elevator has to travel 20m till the ground, then 260 m more.
So, the total distance to travel is 280 m
If the elevator's speed is 5 metres/minute,
Then
Time= Distance/Speed
= 280/5
=56 minutes
Thus the elevator would take almost 1 hour to reach its destination.
Step-by-step explanation:
Answered by
0
Answer:
56 min
Step-by-step explanation:
260+20 = 280 m
Time taken = 280 ÷ 5
= 56 m
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