Question

An elevator descends into a mine shaft at rate of 6m per min if the descent starts from 20 m above the ground level how long will it take to reach -340

Answer 1

Answer:

Speed of elevator = 6m/min

It starts from = 20m above ground

It reaches to = 340m below ground

Distance it covers = 340 + 20 = 360m

Speed = 6m/min

Distance = 360m

Time = Distance / Speed

= 360 / 6 = 60min = 1hour

Answer 2

The elevator will take 1 hour to reach - 340 m

Correct question : An elevator descends into a mine shaft at the rate of 6 m per min. If the descent starts from 20 m above the ground level, how long will it take to reach - 340 m.

Given :

• An elevator descends into a mine shaft at the rate of 6 m per min.

• The descent starts from 20 m above the ground level, and to reach - 340 m.

To find :

The time taken by elevator to reach - 340 m.

Solution :

Step 1 of 2 :

Calculate total distance covered by the elevator

Here it is given that the descent starts from 20 m above the ground level, and to reach - 340 m.

∴ Total distance covered by the elevator

= 20 - ( - 340) m

= (20 + 340) m

= 360 m

Step 2 of 2 :

Calculate the time taken

It is given that the elevator descends into a mine shaft at the rate of 6 m per min.

Hence time taken by elevator to reach - 340 m.

$\displaystyle \sf = \frac{Distance \: covered }{Speed}$

$\displaystyle \sf = \frac{360}{6} \: \: min$

$\displaystyle \sf = 60 \: \: min$

$\displaystyle \sf = 1 \: \: hour$

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