Question

An elevator descends into a mine shaft at the 6 metre per minute how long will it take to reach -370 m, if the Descent starts from 50 m above the ground level ?​

Answer 1

Your Answer:

This Question is a part of time and distance.

So we need to find total distance to find the time taken.

Given:-

• Speed = 6m/min
• Total Distance = (370+ 50)m = 420m   [The minus sign in 370 only shows the direction, so no need to confuse between addition and subtraction of distance, the distance will be added to find whole distance]

To Find:-

• Time taken by elevator to reach -420 m. [minus means downward]

Solution:-

$\tt Speed=\frac{Total\:Distance}{Total\:Time}\\\\\Rightarrow \tt Total\:Time=\frac{Total\:Distance}{Speed}\\\\\Rightarrow \tt Total\:Time=\frac{420m}{6m/min}\\\\\Rightarrow \tt Total\:Time=70min$

So, total time is 70min or 1 hour 10 min

Answer 2

Given:

• An elevator descends into a mine shaft at a speed of 6m/min
• Descent starts from 50m obove the ground level

To find:

• Time taken to reach -370m

Solution:

Total distance = 50m + 370m = 420m

Using the formula is

Speed = distance/time

Simplifying we have

time = distance/speed

→ 420/6

→ 70min. (answer)

Hence, time taken by elevator to reach -370m : 70min