Math, asked by suryanshumohansingh, 3 months ago

An elevator descends into a mine shaft at the rate 7m/min . if the descends starts from 8 m above the ground level , how long will take to reach -340
Please tell me the solution also

Answers

Answered by palatul325

0

Answer:

total decent distance = -378

time taken = 378/7

= 54 min

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