Question

an elevator descends into a mine shaft at the rate 8 m/min. what will be its position after 1 hour?

​

Answer 1

Answer:

Rate of descending = 8m per minute,

therefore position after 60 minutes =8×60=480m below the surface

Answer 2

Step-by-step explanation:

Total distance covered from A to C =12+468=480 m

Speed =8 m/min

Therefore, time = Speed/Total distance covered

= time= 480/

=60 minutes.

Hope its help..⤴️