Question

An elevator descends into a mine shaft at the rate of 10 m/min. if the descent starts from 30 m above the ground level, how long will it take to reach 520 m below the ground level?

answer with explanation. only then you will be marked as brain list :-)
unnecessary answers will be reported

Answer 1

Answer:

Elevator cover a distance of 520+30 = 550 m

now time taken =

$\frac{distance}{speed} = \frac{550}{10} = 55 \: min$

Answer 2

Answer:

$it \: will \: take \: 55 \: min$