Math, asked by meghaparamkar, 8 months ago

an elevator descends into a mine shaft at the rate of 10m/min . if the descent starts from 250m above the ground level how long will it take to reach (-450m).​

Answers

Answered by daddyshruck
0

Answer: the answer would be 25 seconds

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Answered by navadeepsai11
2

Answer:

Total distance to be covered = 250 - (-450) = 700 m

Speed = 700/10 = 7 min

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