Math, asked by santoshkumargupta118, 9 months ago

An elevator descends into a mine shaft at the rate of 10m/min.If the descends starts from 20m above the ground level.How long will it take to reach -430m.​

Answers

Answered by avimahthaofficial
0

Answer:

Here, since the descend starts from 20 m above ground level, the elevator will have to cover an extra distance of 20m. So, total distance = 370 + 20 = 390 m. Hence, time required to go 370 m below ground level when the elevator starts from 20 m above, is 65 minutes or 1 hour and 5 minutes.

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