an elevator descends into a mine shaft at the rate of 10m per minute if the distance start from 30 m above the ground level how long will it take to reach 520 M below the ground level
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Initially the elevator is 30 m above the ground
It has to go 520 m below the ground hence
total distance =30+520=550m
Time taken by elevator to descend 10 m is 1 minute
then time taken to descend 1 m =1/10 minute
now for 550 m
time needed
= 550m =550/10 = 55 minutes
It has to go 520 m below the ground hence
total distance =30+520=550m
Time taken by elevator to descend 10 m is 1 minute
then time taken to descend 1 m =1/10 minute
now for 550 m
time needed
= 550m =550/10 = 55 minutes
casey3:
hiiii
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Answer is 55 mins...
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