Math, asked by sahil6173, 11 months ago

An elevator descends into a mine shaft at the rate of 13m/min. If the descend starts from 20 m above
the ground level, how long will it take to reach-240 m?​

Answers

Answered by kundanroy19
78

Answer:

Given:rate=13m/min,height from ground level=20m,depth of mine from ground level=240m

Therefore total height =240+20=260m

Total time taken to reach the 240m=260/13=20min...answer

Answered by aksh92
41

Step-by-step explanation:

Since it is 20 m above ground level (given)

Total distance =240+20=260m

Given speed =13 m/min

Total time =Total distance /Speed

=260/13=20 min

It will take 20 min or 1200 s

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