Question

an elevator descends into a mine shaft at the rate of 19/4 Meter per minute. if it begins to descend from 15/2meter above the ground what will be it's position after 18 minutes from the ground?​

Answer 1

Answer:an elevator descends into mine shaft at the rate of 5 meter per minute.

so for 1 min elevator descends 5metres.

the position of the elevator after one hour =

we know 1 hour =60 min so 60min x 5metres=300 meters..

but the elevator began to descend from 15 meters above so,

300-15="285metres."

and its position after 45 mins is 45metres x 5 mins=225 meters.

 and the elevator has descended from 15 meters above so

225-15 meters="210metres

Answer 2

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