Math, asked by sushmitanaikdessai, 3 months ago

An elevator descends into a mine shaft at the rate of 3m/min. If the descent
starts from 10 m above the ground level, how long will it take to reach
-260 m ?​

Answers

Answered by GaneshRM2006
3

Answer:

total distance = -260+10 = -250m

speed of elevator = 3m/min

time taken = -250m÷-3m/min

                  = 83.33min

                  = 1hr 33min

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