An elevator descends into a mine shaft at the rate of 3m/min. If the descent
starts from 10 m above the ground level, how long will it take to reach
-260 m ?
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Answer:
total distance = -260+10 = -250m
speed of elevator = 3m/min
time taken = -250m÷-3m/min
= 83.33min
= 1hr 33min
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