Question

An elevator descends into a mine shaft at the rate of 3m per minute. If the descents starts from 20m above the ground level, how long will it take to reach —160m.​

Answer 1

Answer:

If I = [sec? 2xdx , then the value of 1 is 4 1) tan x + c 2) tan 2x + c 5 tan 2x 3) + c 4) cot 2 x + c 2

Answer 2

Total distance=initial position- final position

=20-(-160)

=20+160

=180m

Now,

Elevator descends 3m/min

Elevator travels 3m in 1min

Elevator travels 1m in 1/6min

Elevator travels 180 m = 180×1/6min

=180/6

= 30 min

.

. . IT TAKES 30 MIN TO REACH -160 M

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