An elevator descends into a mine shaft at the rate of 4 m per minute what will be its position after one hour. If it begins to descend from 10 m above the ground , what will be its position after 40 minutes from the ground ? represent distance above the ground by a positive integer and below the ground by a negative integer .
Answers
Answer:
Answer: The shaft will be 240 m below ground after an hour.
Answer: It will be 150m below ground after 40 mins
Step-by-step explanation:
Given,
Rate = 4m/min
1 min = 4m
60 mins = 4 x 60 = 240 m
Answer: The shaft will be 240 m below ground after an hour.
Find the distance traveled in 40 mins:
1 min = 4m
40 min = 4 x 40 = 160 m
Find the relative distance of the shaft after 40 mins:
Given that it started from 10m above ground
Distance = 10 - 160 = -150m
Answer: It will be 150m below ground after 40 mins
Answer:
Hopw it helps.
Step-by-step explanation:
The speed of the elevator = 4m / min
It begins at 10 m above the ground.
Then after 40 min, it would be ⇒ 40 * 4 = 140. [ as it was 10 m above the ground + 10 - 140 = -130m is the distance from the ground]
After 1 h = 60 * 4 = 240, then it's position will be - 230m.