Math, asked by joyparashar6, 1 year ago

an elevator descends into a mine shaft at the rate of 4m per minute . if the descent starts from 10m above the ground level , how long will it take to reach -230 m ?


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Answers

Answered by tanmaykachroo
1
time=distance/speed
time = 240/4 mpm
time = 60 min. = 1 hour

tanmaykachroo: 240m
joyparashar6: there is -230 m in ques. read last line
tanmaykachroo: what is the answer?
tanmaykachroo: what is the correct answer
joyparashar6: i dont no pls u help me
tanmaykachroo: it is correct
tanmaykachroo: let me explain
tanmaykachroo: 4m per i min okk . .. . . . . . . . . 60 * 4 = 240 m
AcharyaVII: Learn to give more explanations please
tanmaykachroo: okk
Answered by goyalp
0
10 +230 m = 240 m =240÷4 =60 minute =1 hr
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