Question

AN ELEVATOR DESCENDS INTO A MINE SHAFT AT THE RATE OF 5 METRE PER MINUTE. WHAT WILL BE ITS
POSITION AFTER ONE HOUR FROM GROUND?​

Answer 1

Answer:

RATE OF DESCEND PER MINUTE = 5 METRE

NUMBER OF MINUTES IN AN HOUR = 60

TOTAL DESCEND = 60 * 5

                              = 300 M

SO IT WILL BE AT A POSITION OF 300 M BELOW THE GROUND OR -300 M

 PLS MARK IT THE BRAINIEST

Answer 2

Answer:

300 m below ground level.

Step-by-step explanation:

Sol: Since the elevator is going down, the distance covered by it will be

represented by a negative integer.

Change in position of the elevator in one minute = – 5 m

Position of the elevator after 60 minutes = (–5) × 60 = – 300 m