Question

An elevator descends into a mine shaft at the rate of 5 metres per minute.What will be its position after one houre?

Answer 1

Answer:

300 m below ground level.

Step-by-step explanation:

Sol: Since the elevator is going down, the distance covered by it will be

represented by a negative integer.

Change in position of the elevator in one minute = – 5 m

Position of the elevator after 60 minutes = (–5) × 60 = – 300 m