Question

An elevator descends into a mine shaft at
the rate of 5 metres per minutes. What will
be its position after 1 hour​

Answer 1

Answer:

300m below street level

Step-by-step explanation:

speed: 5m/s

time:1 hr/60min

distance covered:s×t

=5×60

=300

therefore, the answer is 300 m

Answer 2

Answer:

300

Step-by-step explanation:

1 hr =60 min

the rate at which elevator descent is 5m/min.It means in 1 min it descents 5 m

therefore in 1hr =60 min its  position will be 60*5=300m

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