An elevator descends into a mine shaft at the rate of 5 metre per minute.What will be its position after one hour? If it begins to descend from 15 m above the ground, what will be its position after 45 minutes
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Answered by
401
an elevator descends into mine shaft at the rate of 5 meter per minute.
so for 1 min elevator descends 5metres.
the position of the elevator after one hour =
we know 1 hour =60 min so 60min x 5metres=300 meters..
but the elevator began to descend from 15 meters above so,
300-15="285metres."
and its position after 45 mins is 45metres x 5 mins=225 meters.
and the elevator has descended from 15 meters above so
225-15 meters="210metres."
hope this helps u.
so for 1 min elevator descends 5metres.
the position of the elevator after one hour =
we know 1 hour =60 min so 60min x 5metres=300 meters..
but the elevator began to descend from 15 meters above so,
300-15="285metres."
and its position after 45 mins is 45metres x 5 mins=225 meters.
and the elevator has descended from 15 meters above so
225-15 meters="210metres."
hope this helps u.
Answered by
0
Answer:
-300m; -115m
Step-by-step explanation:
thank yougb
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