Question

An elevator descends into a mine shaft at the rate of 5 meter per minute. (i) What will be its position after one hour? (ii) If it begins to descend from 15 m above the ground, what will be its position after 45 minutes?​

Answer 1

Answer:

(I)300m under the ground

(ii) 210m under the ground

Step-by-step explanation:

1.

mine shaft descends into mine shaft : 5m/minute

mine shaft descends into mine shaft in 1 hour = 60×5=300 meters

2.

position of mine shaft= 15m above ground

15÷5=3

mine shaft descends in 45 minutes = 45×5=225meters

225-15=210