Question

An elevator descends into a mine shaft at the rate of 5 meters per minute. What will be its position after one hour?

Answer 1

Answer:

after 1hour=5×60=300. It's position will be=15-300=-285=285m below the ground.

Answer 2

Answer:

Answer. after 1hour=5×60=300. It's position will be=15-300=-285=285m below the ground.

Step-by-step explanation:

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