Math, asked by khushchaudhari053, 11 days ago

an elevator descends into a mine shaft at the rate of 5 metre per minute. what will be its position after one hour? if it begins to descend from 15 m above the ground, what will be its position after 45 minutes?

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Answered by pranav17087
12

Answer:

after 1hour=5×60=300. It's position will be=15-300=-285=285m below the ground.

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Answered by ritachaudhary1011
6

Answer:

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