Math, asked by Abhishekpatil8446, 1 month ago

An elevator descends into a mine shaft at the rate of 5 minutes if there was any traffic from 8 minut above the ground level how long will take a week 42 minutes means 42 minutes below the ground level

Answers

Answered by prakritiverma71
0

solution :

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground.

Similar questions