. An elevator descends into a mine shaft at the rate of 5 m/min. If
the descent starts from 10 m above the ground level, how long will
it take to reach -350 m.
Answers
Answered by
3
Answer:
Descends 5 m in 1 min
Descends 1 m in 1/5 min
Descends -340(-350+10)m in (1 × -340)/5
= 68 mins or 1 hr 8 min
Therefore the machine takes 1 hr 8 min to descends from 10 m above the ground to 350 m below the ground
Similar questions