An elevator descends into a mine shaft at the rate of 5 m/min. If the descend starts from 15m above the ground, by how long will it take to reach 350 m deep from the ground?
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If it begins to descend from 15 metres above the ground, what will position after 45 minutes? (i) Displacement = Velocity x Time = -5 m/min x 60 min = -300 m.
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