An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m (means -42 m) below the ground level ?
Answers
Answered by
39
Answer:
1 hour
Step-by-step explanation:
Consider the elevator to be at constant speed and the destination to be 350m below ground level, the elevator has to travel 10m till the ground, then 350m more
So, total distance to travel is 360m
If the elevators speed is 6m/min,
Time= distance/speed
=360/6
=60 minutes
=1 hour.
Answered by
1
To find:
Time taken to reach 42 m below the ground level (means - 42 m)
Step-by-step explanation:
Since the elevator starts from 8 m above the ground level, the distance between 8 m above the ground level and 42 m below the ground level is 8 - (- 42) = 8 + 42 = 50 m
Here the speed of the elevator is 5 m/min
Thus the required time
= total distance ÷ speed of the elevator
= 50 ÷ 5 min
= 10 min
Answer:
It will take 10 minutes to reach 42 m below the ground level.
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