Question

An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m (means-42 m) below the ground level ?​

Answer 1

Answer:

It will take the elevator 10 minutes to reach the mine.

Step-by-step explanation:

Rate of desend per minute - 5 mt  

Starting point above ground level - 8 mt                      

Destination below ground level - 42 mt                          

Overall distance to be travalled - 50 mt

To find the answer, we need to add the distance from the starting point (8mt above ground) with the destination (42mt below ground) assuming the mine shaft is travalling at the constant speed.  

50mt/5 = 10minutes.

Answer 2

Solution :-

Let , above the ground height is taken as positive { right side of zero on number line } and below ground level is taken as negative .{ Left side of zero on number line. }

So,

→ Speed of elevator descends into mine = 5 m/min .

Now, Distance covered is from 8 m above ground level to 42 m below ground level is { according to number line } :-

<---(-42)m --------------------------------0------------8m ------>

then,

→ Distance covered = 8m + 42m = 50 m .

therefore,

→ Time taken = Distance / Speed = 50/5 = 10 minutes (Ans.)

Hence, time taken by elevator to reach 42 m below the ground level is 10 minutes .

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