An elevator descends into a mine shaft at the rate of 5 m/min. If the descent
starts from 8m above the ground level, how long will it take to reach 42 m
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Answer:
Step-by-step explanation:
Speed of elevator = 5 m/min
Starting point = 8 m above the ground
Final point = 42 m deep
Total distance = (8 + 42) m
= 50 m
Time it will take to reach its destination :-
= (50 x 5) mins
= 250 mins
= 4 hours and 10 minutes
hope it helps :)
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