Question

An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m (means -42 m) below the ground level ?​

Answer 1

Answer:

It will take 6 min 48 sec. Please mark me as brainliest.

Step-by-step explanation:

We will denote downwards as - and upwards as +

Speed = -5m/min

Distance = Final point - Starting Point

= -42m - (-8m)

= -42m + 8m

= -34m

Time = Distance/Speed

= -34/-5

= 34/5

= 6.8 min ( since speed was in min)

= 6   8/10  min

= 68/10 min

= 408/60 min

= 408 sec

= 6 min 48 sec

Answer 2

If the descent starts from 8m above the ground level then the time it will will reach the below the ground level is 1 hour 11 min. I am sorry if this is wrong.